PC Chips M571 (V3.2) undocumented voltage settings
 --------------------------------------------------
 
 The following schematic diagram shows the relevant section of the
 on-board power supply (reverse engineered):
 
                                  6K81    11K5    30K1 Resistor
                              10K0    9K53    22K1      values
 
                              2V5 3V5 3V3 3V2 2V9 2V8  Jumper ID
     From  _____  _____
     Load  |    \/    |14     R88 R89 R90 R91 R92 R93  Circuit ref
      |    |          |--------|---|---|---|---|---|
      |   1| |\Error  | Vref  |-| |-| |-| |-| |-| |-|
 Vout |----|-| \_Amp  | +5V   | | | | | | | | | | | |  Resistors
       ____|_| /      |       |-| |-| |-| |-| |-| |-|
     V |  2| |/       |        |   |   |   |   |   |
       |   |          |        |   O   O   O   O   O    Jumpers
       |   | KA7500B  |        |   O   O   O   O   O     JP6   
       |   |__________|        |   |   |   |   |   |
       |                       |---|---|---|---|---|
       |_______________________|
                               |
                         R79  |-|
                         10K2 | |
                              |-|
                               |
                              _|_
 
 
 
 
 The following table lists the actual voltages for the various
 jumper selections (0=no jumper, 1=jumper installed). It appears
 that the design provides an 0.08V margin to allow for ripple and
 ohmic losses.
 
 Jumpers       nominal V     V - 0.08
 3V5-2V8     (at regulator) (at CPU socket)
 
 00000          2.53          2.45
 OOOO1          2.88          2.8 
 OOO1O          2.99          2.91 
 OO1OO          3.28          3.2 
 O1OOO          3.38          3.3 
 1OOOO          3.58          3.5 
 
 
 Q. How does one obtain a core voltage of 2.4V or 2.2V?
    ---------------------------------------------------
 
 Core voltages less than 2.5V can be obtained by connecting a suitable
 resistor in parallel with R79 as follows (2.2V shown):
 
                                  6K81    11K5        30K1 Resistor
                              10K0    9K53    22K1         values
 
                              2V5 3V5 3V3 3V2 2V9 2V8  Jumper ID
     From  _____  _____
     Load  |    \/    |14     R88 R89 R90 R91 R92 R93  Circuit ref
      |    |          |--------|---|---|---|---|---|
      |   1| |\Error  | Vref  |-| |-| |-| |-| |-| |-|
 Vout |----|-| \_Amp  | +5V   | | | | | | | | | | | |  Resistors
       ____|_| /      |       |-| |-| |-| |-| |-| |-|
     V |  2| |/       |        |   |   |   |   |   |
       |   |          |        |   O   O   O   O   O    Jumpers
       |   | KA7500B  |        |   O   O   O   O   O--|  JP6
       |   |__________|        |   |   |   |   |   |  |
       |                       |---|---|---|---|---|  |
       |_______________________|                      |
                               |                      |
                         R79  |-|                    |-|
                         10K2 | |                    | | 39K
                              |-|                    |-|
                               |                      |
                              _|_                    _|_
 
 
 
 In the above case there is effectively a 39K resistor in parallel with
 R79. All other jumpers are removed. The ground side of the 39K resistor
 can be connected to a nearby ground pin such as pin 3 of the speaker 
 connector (J3), pin 5 of the keylock connector (J3), or pin 3 of the 
 fan power connector (J2). The nominal output of the regulator is 2.23V.
 
 For 2.3V (nominal 2.33V), a 62K resistor should be used.
 For 2.4V (nominal 2.43V), a 120K resistor should be used.
 
 The required resistance can be computed using the formula:
 
  R = 102 * Vcore / (51- 20.2 * Vcore)
 
 Conversely, a resistance R will produce the following core voltage:
 
  Vcore = 51 * R / (102 + 20.2 * R)
 

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 This page was last modified on 17 July 2002